2x^2-8x-10=x+8

Solution for 2x^2-8x-10=x+8 equation:

2x^2-8x-10=x+8

We move all terms to the left:

2x^2-8x-10-(x+8)=0

We get rid of parentheses

2x^2-8x-x-8-10=0

We add all the numbers together, and all the variables

2x^2-9x-18=0

a = 2; b = -9; c = -18;
Δ = b2-4ac
Δ = -92-4·2·(-18)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-15}{2*2}=\frac{-6}{4}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+15}{2*2}=\frac{24}{4}
=6
$